Using Ohm's law V = IR, what is the voltage across a 6 Ω resistor carrying 2 A?

Using Ohm's law V = IR, what is the voltage across a 6 Ω resistor carrying 2 A?

• A. 12 V
• B. 3 V
• C. 6 V
• D. 8 V

Answer: (A)

Ohm's law says voltage equals current times resistance. With a 6-ohm resistor carrying 2 amperes, the voltage drop is V = I × R = 2 A × 6 Ω = 12 V. So the voltage across the resistor is 12 volts. If the voltage were different, it would require a different resistance (for example, 3 V with 2 A would need 1.5 Ω, or 8 V would need 4 Ω), but given the values provided, 12 V is correct.

Ohm's law says voltage equals current times resistance. With a 6-ohm resistor carrying 2 amperes, the voltage drop is V = I × R = 2 A × 6 Ω = 12 V. So the voltage across the resistor is 12 volts. If the voltage were different, it would require a different resistance (for example, 3 V with 2 A would need 1.5 Ω, or 8 V would need 4 Ω), but given the values provided, 12 V is correct.